Introduction to help me solve my algebra problems :

Algebra is the branch of mathematics concerning the study of the rules of operations and relations, and the constructions and concepts arising from them, including terms, polynomials, equations and algebraic structures. The part of algebra called elementary algebra is often part of the curriculum in secondary education and introduces the concept of variables representing numbers. Statements based on these variables are manipulated using the rules of operations that apply to numbers, such as addition etc. This can be done for a variety of reasons, including equation solving.This is very helpful to solve the real life problems.

Help me solve my algebra problems

Let us solve expressions problems

Ex 1: Solve: 12x + 4x

Solution: 12x + 4x = (12 + 4) x

12x and 4x has the common term x.so. we take ‘x’ outside.

12x + 4x = 16 x

Ex 2: Solve: 6y-4y

Solution: 6y and 4y has the common term y.So, we take ‘y’ outside

6y – 4y = (6-4)y

6y – 4y = 2y

Ex 3: 3x + 4y + 6x -6y

Solution: 3x + 6x – 6y + 4y

Add the like terms

(3 + 6)x + (-6 + 4)y

Simplify the expression

9x – 2y

Answer : 9x – 2y

Ex 4: Solve the expression : 3pq^3 × 4qr

Solution: 3pq^2× 4qr

= 3 × p × q × q × 4 × q × r

= 3 × 4 × p × q × q × q × r

= 12 × p × q^3 × r

= 12pq4r

Ex 5: Solve the expression : -2a^3b× 3ab^2c

Solution: -2a^3b× 3ab^2c

= -2 × 3× a^3× a × b × b^2× c

If the base is same then those exponents are added and simplify the expression,

= -6× a^4× b^3× c

= -6a^4b^3c

Let us evaluate expressions problems

Ex 6: Evaluate the expression (1 + x) × 2 + 12 ÷ 3 – x when x = 5.

Solution: Here,we substitute the value of 5 in the place of x,

(1 + x) × 2 + 12 ÷ 3 – x becomes

(1 + 5) × 2 + 12 ÷ 3 – 5 = 6 × 2 + 12 ÷ 3 – 5

= 12 + 4 – 5

= 11.

Help me solve my algebra equations problems:

Ex 7: 12x+4 = 16

Solution:12x+4 =16

Subtract 4 on both sides ,we get

12x +4 -4 = 16-4

12x = 12

Divide both sides by 12 ,we get

X = 1

Check: Substitute x=1 on given equation:

12x + 4 =16

12(1) + 4 =16

12 + 4 =16

16 = 16

Ex 8: Solve: ‘(x)/(4)’ +3 = 17

Solution : ‘(x)/(4)’ +3 = 17

Subtract 3 on both sides,

‘(x)/(4)’ +3 -3 =17-3

‘(x)/(4)’ =14

Multiply 4 on both sides,

‘(x)/(4)’ * 4 = 14 *4

x= 14 * 4

x = 56

Check:Substitute x = 56 on given equation:

‘(x)/(4)’ +3 = 17

‘(56)/(4)’+3 = 17

14 + 3 = 17

17 = 17

Help me solve my Algebra Multi-Step Equations:

Ex :9 Solve 3(x + 1) – x = 5

Solution:

3(x + 1) – x = 5

3x + 3 – x = 5 (use distributive property)

2x + 3 = 5 (combine like terms)

2x + 3 – 3 = 5 – 3

2x =2

x = 1

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